4y^2=19.36

Solution for 4y^2=19.36 equation:

4y^2=19.36

We move all terms to the left:

4y^2-(19.36)=0

We add all the numbers together, and all the variables

4y^2-19.36=0

a = 4; b = 0; c = -19.36;
Δ = b2-4ac
Δ = 02-4·4·(-19.36)
Δ = 309.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{309.76}}{2*4}=\frac{0-\sqrt{309.76}}{8}
=-\frac{\sqrt{}}{8}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{309.76}}{2*4}=\frac{0+\sqrt{309.76}}{8}
=\frac{\sqrt{}}{8}
$